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Finding the unknown value (S9)

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1

1	1	–	1	1	=
	3			5

2

3	–	1	=
5		6

3

	5	–	x	=	1
	6				2

4

x	–	2	=	2
		3		15

5

	2	–	x	=	1
	4		3		6

6

	x	–	1	=	4
	5		3		15