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Finding the unknown value (S6)

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1

1	2	–	1	2	=
	3			5

2

3	–	1	=
5		6

3

	3	–	x	=	4
	5				15

4

x	–	2	=	7
		5		20

5

	1	–	x	=	1
	3		4		12

6

	x	–	1	=	5
	3		4		12