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Finding the unknown value (S37)

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1

1	1	–	1	1	=
	2			3

2

3	–	1	=
5		2

3

	1	–	x	=	1
	4				20

4

x	–	1	=	1
		2		3

5

	5	–	x	=	1
	6		3		2

6

	x	–	1	=	7
	5		6		30