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Finding the unknown value (S33)

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1

1	1	–	4	=
	4		5

2

5	–	1	=
6		4

3

	2	–	x	=	1
	3				2

4

x	–	1	=	1
		6		2

5

	3	–	x	=	1
	5		2		10

6

	x	–	1	=	1
	3		4		12