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Finding the unknown value (S32)

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1

5	–	1	=
6		2

2

3	–	3	=
4		5

3

	1	–	x	=	1
	2				10

4

x	–	1	=	11
		5		20

5

	2	–	x	=	5
	3		4		12

6

	x	–	1	=	1
	2		6		3