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Finding the unknown value (S31)

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1

1	3	–	5	=
	7		6

2

2	–	3	=
3		5

3

	3	–	x	=	1
	4				4

4

x	–	1	=	5
		3		12

5

	2	–	x	=	7
	3		5		15

6

	x	–	1	=	13
	5		6		30