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Finding the unknown value (S28)

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1

1	1	–	7	=
	4		8

2

2	–	1	=
5		6

3

	2	–	x	=	5
	3				12

4

x	–	1	=	1
		4		12

5

	3	–	x	=	7
	4		5		20

6

	x	–	1	=	4
	5		3		15