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Finding the unknown value (S26)

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1

1	3	–	1	=
	4		2

2

2	–	1	=
3		5

3

	1	–	x	=	1
	5				30

4

x	–	1	=	1
		6		6

5

	3	–	x	=	3
	4		5		20

6

	x	–	2	=	1
	6		3		6