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Finding the unknown value (S25)

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1

1	1	–	2	=
	2		3

2

3	–	3	=
4		5

3

	1	–	x	=	1
	4				20

4

x	–	1	=	3
		4		20

5

	3	–	x	=	1
	4		2		4

6

	x	–	1	=	7
	5		3		15