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Finding the unknown value (S24)

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1

1	5	–	1	1	=
	6			5

2

1	3	–	1	1	=
	5			3

3

	3	–	x	=	7
	5				20

4

x	–	1	=	1
		6		12

5

	3	–	x	=	7
	4		6		12

6

	x	–	1	=	1
	6		2		3