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Finding the unknown value (S22)

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1

1	2	–	1	=
	5		6

2

1	–	1	=
2		6

3

	2	–	x	=	5
	3				12

4

x	–	1	=	7
		4		12

5

	2	–	x	=	4
	3		5		15

6

	x	–	1	=	1
	2		6		3