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Finding the unknown value (S20)

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1

2	3	–	1	1	=
	5			3

2

1	3	–	1	1	=
	5			3

3

	3	–	x	=	1
	4				4

4

x	–	1	=	3
		5		10

5

	2	–	x	=	1
	5		3		15

6

	x	–	2	=	1
	4		3		12