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Finding the unknown value (S19)

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1

4	–	1	=
5		2

2

1	3	–	1	1	=
	4			3

3

	2	–	x	=	5
	3				12

4

x	–	1	=	1
		6		30

5

	2	–	x	=	7
	5		6		30

6

	x	–	1	=	1
	6		2		3