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Finding the unknown value (S15)

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1

2	–	1	=
3		6

2

5	–	4	=
6		5

3

	3	–	x	=	13
	4				28

4

x	–	4	=	5
		7		28

5

	4	–	x	=	2
	5		3		15

6

	x	–	1	=	1
	5		6		30