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Finding the unknown value (S1)

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1

1	1	–	1	=
	2		3

2

3	–	1	=
5		3

3

	1	–	x	=	1
	2				3

4

x	–	2	=	4
		5		15

5

	5	–	x	=	4
	6		6		6

6

	x	–	1	=	5
	3		4		12